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Day 1 - (23 April 2024)
Q.1) A group of 630 children is seated in rows for a group photo session. Each row contains three less children than the row in front of it. Which one of the following number of rows is not possible? (2014)
(a) 3
(b) 4
(c) 5
(d) 6
Solution: (d)
Let no of children be x, x + 3, x + 6, x+ 9, x +12, x+ 15 ...........
And these children are in Rows - R1, R2, R3, R4, R5, R6….
Rows given as 3, 4, 5, 6.. So putting these values-
When R = 3;
x+x+3+x+6 = 630; 3x+9= 630; 3x= 621; x= 207
When R = 4;
x+x+3+x+6+x+9= 630; 4x+18= 630; 4x= 612; x= 153
When R= 5;
x+x+3+x+6+x+9+x+12= 630; 5x+ 30= 630; 5x= 600; x= 120
When R = 6;
x+x+3+x+6+x+9+x+12+x+15 = 630; 6x+45 = 630; 6x = 585; X = 97.5
Because x is not an integer. So, R = 6 is the answer.
Q.2) If Sohan while selling two goats at the same price , makes a profit of 10% on one goat and suffers a loss of 10% on the other one (2014)
(a) He makes no profit, no loss.
(b) He makes a profit of 1%.
(c) He suffers a loss of 1%.
(d) He suffers a loss of 2%.
Solution: (c)
If profit and loss percent on two different items is equal, then there will always be a loss.
Simply putting values in the formula - we get
% final loss = (%loss * % gain)/ 100 = (10 * 10/ 100) = 1% loss.
Day 2 - (24 April 2024)
Q.3) In a row ‘A’ is in the 11th position from the left and B is in the 10th position from the right. If ‘A’ and ‘B’ interchange then A becomes 18th from the left. How many persons are there in the row other than A and B ?
(2014)
(a) 27
(b) 26
(c) 25
(d) 24
Solution: (c)
No. of students between A and B in the 1st arrangement = 17 - 11 = 6.
Total no. of students except A and B is = 10 + 6 + 9 = 25
Q.4) Location of B is north of A and the location of C is east of A. The distances AB and AC are 5 km and 12 km respectively. The shortest distance in km between the locations B and C is- (2014)
(a) 60
(b) 13
(c) 17
(d) 7
Solution: (b)
To find the distance between B and C, a right triangle is considered where AB and AC are the sides and BC is the hypotenuse.
Applying the Pythagorean theorem, the shortest distance BC is found to be 13 km.
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Day 3 - (25 April 2024)
Q.1) Five persons fire bullets at a target at an interval of 6, 7, 8, 9 and 12 seconds, respectively. The number of times they would fire the bullets together at the target in an hour is - (2014)
(a) 6
(b) 7
(c) 8
(d) 9
Solution: (b)
To find out the time gap after which they will first hit the target, calculate the LCM of 6 7 8 9 12.
LCM = 504 sec
∴ In 1 hr = 3600 sec
No. of time they will hit together is 3600/504 = 7 times in an hour.
Q.2) There are seven persons up on a ladder A B C D E F and G not in that order. A is further up than E but is lower than C. B is in the middle. G is between A and B. E is between B and F. If F is between E and D the person on the bottom step of the ladder will be - (2014)
(a) B
(b) F
(c) D
(d) E
Solution: (c)
As per the given information, B is in the middle.
Other information -
A is further up than E but is lower than C.
G is between A and B.
E is between B and F.
F is between E and D.
This means that there is a vacancy in between A and B.
If A is two steps above B, G will be on the 5th step from bottom and C will be on the top most step. The resulting arrangement is-
Hence, D is on the last step.
Day 4 - (26 April 2024)
Q. 1 A worker reaches his factory 3 minutes late if his speed from his house to the factory is 5 km/hr If he walks at a speed of 6 km/hr, then he reaches the factory 7 minutes early. The distance of the factory from his house is-
(2014)
(a) 3 km
(b) 4 km
(c) 5 km
(d) 6 km
Solution: (c)
Let the distance be x km,
x/5 - 3/60 = x/6 + 7/60
x/5 - x/6 = 10/60
x/30 = 1/6
x = 5 km
Q.2 Liberty therefore is never real unless the Government can be called to account when it invades rights.
Which one of the following is the best justification of the above statement ?
(2014)
(a) In the realization that the government can be brought to book in a court of law.
(b) In identifying a man as a political unit in a way which distinguishes him from other citizens.
(c) In a decentralized society wherein the basic needs of men can find satisfaction.
(d) In the understanding that liberty and restraints are complementary.
Solution: (d)
- In the understanding that liberty and restraints are complementary is the statement which best explains why Liberty therefore is never real unless the Government can be called to account when it invades rights.
Day 5 - (27 April 2024)
Q. 1 If the third day of a month is Monday, then which day of the week will be the fifth day from the 21st of that month? (2014)
(a) Monday
(b) Tuesday
(c) Wednesday
(d) Friday
Solution: (c)
3rd day ⇒ Monday
10th day ⇒ Monday
17th day ⇒ Monday
24th day ⇒ Monday
Fifth day from the 21st is the 26th day.
So the 26th day is Wednesday.
Q. 2 For a charity show, the total tickets sold were 420. Half of these tickets were sold at the rate of Rs. 5 each, one-third at the rate of Rs. 3 each and the rest for Rs.2 each. What was the total received? (CSE 2014)
(a) Rs. 900
(b) Rs.1540
(c) Rs.1610
(d) Rs.2000
Solution: (c)
Total tickets sold = 420
Half of the tickets sold at the rate of Rs. 5 each.
Therefore, 210 tickets sold = 210 × 5 = Rs 1050
One third ticket sold for Rs. 3 i.e 1/3 of 420 = 140 tickets sold at Rs. 3 each.
Collection through it = 140 × 3 = Rs 420
The Remaining 70 tickets were sold at the rate of Rs. 2 each.
So collection = 70 × 2 = Rs 140
Total collection = 1050 + 420 + 140 = 1610.
Day 6 - (29 April 2024)
Q.1 Two cars start towards each other, from two places A and B which are at a distance of 160 km. They start at the same time, 8:10 AM. If the speeds of the cars are 50 km and 30 km per hour respectively, they will meet each other at- (2014)
(a) 10:10 AM
(b) 10:30 AM
(c) 11:10 AM
(d) 11:20 AM
Solution: (a)
A --------------------X km--------------P -------------- (160−X) km-----------------B
Speed of B= 30 kmph
Let time taken to meet at point P Is the same as both trains started at the same time . Now,
Time taken to travel X km by A=X/50 .........(i)
Time taken to travel (160−X) km by B=(160−X)/30 ............(ii)
Comparing equation (i) and (ii), we have
X/50 = (160−X)/30 ⇒ 3X=800−5X ⇒8X=800 ⇒X=100 km
Time taken by A to travel 100 = 100/50=2 hours.
So, they will meet each other at 10:10 AM.
Q.2 Four persons Alok, Bhupesh, Chander and Dinesh have a total of Rs.100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact Rs.5 more than Dinesh has. Who has the maximum amount of money? (2014)
(a) Alok
(b) Bhupesh
(c) Chander
(d) Dinesh
Solution: (a)
Alok + Bhupesh + Chander + Dinesh = Rs.100
Alok + Bhupesh = Chander + Dinesh
OR
Alok + Bhupesh = Chander + Dinesh = Rs.50
Also, 2Chander = Dinesh
Chander = Rs 16.67
Dinesh = Rs 33.33
Alok = 33.33 + 5 = 38.33
Bhupesh = 50 - 38.33 = Rs 11.67
So, Alok has the highest amount of money.
Day 7 - (30 April 2024)
Q. 1 The letters L, M, N, O, P, Q, R, S and T in their order, are substituted by nine integers 1 to 9 but not in that order. 4 is assigned to P. The difference between P and T is 5. The difference between N and T is 3. What is the integer assigned to N? (2014)
(a) 7
(b) 5
(c) 4
(d) 6
Solution: (d)
Given that P = 4 and T - P = 5
Also, T - N = 3.
Now, T - P = 5; T - 4 = 5; T = 9
And, 9 - N = 3; N = 6.
So N = 6.
Q.2 The number of deaths among the army personnel is 8 in 1000 but among the civilian population it is 20 per 1000. Which one of the following inferences can be drawn from this statement? (2014)
(a) It is better to join the army.
(b) The relationship is fortuitous.
(c) The Quality of Life Index is very high within the armed forces.
(d) The groups cannot be compared due to their heterogeneity.
Solution: (d)
- Army personnel go through training and are generally fit. While civilians are diverse which includes all age groups.
- Thus both are heterogenous and cannot be compared.
Day 8 - (1 May 2024)
Q.1 A and B decide to travel from place X to place Y by bus. A has Rs.10 with him and he finds that it is 80% of the bus fare for two persons. B finds that he has Rs. 3 with him and hands it over to A. In this context which one of the following statements is correct ? (CSE 2014)
(a) Now the money A has is just enough to buy two tickets.
(b) A still needs Rs2 for buying the tickets.
(c) After buying the two tickets A will be left with 50 paise.
(d) The money A now has is still not sufficient to buy two tickets.
Solution: (c)
A has Rs 10, and if B gives Rs.3 to A, now A has Rs.13
Cost of 2 tickets = 80% of x = 10
x= Rs 12.50
So, A is left with Rs.13 – 12.50 = 50 paise.
Q.2 As per agreement with a bank a businessman had to refund a loan in some equal installments without interest. After paying 18 installments he found that 60 percent of his loan was refunded. How many installments were there in the agreement ? (CSE 2014)
(a) 22
(b) 24
(c) 30
(d) 33
Solution: (c)
Let the amount in each installment be x
And total amount be a
Number of installments = Total amount / Amount in each installment
18 = (60/100) × a / x
18x = (60/100) x a
(18 × 100)/60 = (a/x)
a/x = 30
∴ Number of installments are 30
Day 9 - (2 May 2024)
Q.1 Consider that-
- A is taller than B
- C is taller than A.
- D is taller than C.
- E is the tallest of all. (CSE 2014)
If they are made to sit in the above order of their height, who will occupy the mid position?
(a) A
(b) B
(c) C
(d) D
Solution: (c)
- The sequence as per data-
Thus ‘C’ occupies the mid position.
Q.2 Consider the following statements-
There are six villages A B C D E and F.
- F is 1 km to the west of D.
- B is 1 km to the east of E.
- A is 2 km to the north of E.
- C is 1 km to the east of A.
- D is 1 km to the south of A. (CSE 2014)
Which three villages are in a line ?
(a) A C B
(b) A D E
(c) C B F
(d) E B D
Solution: (b)
- Drawing a diagram based on the statements given.
Hence ADE are in a line.
Day 10 - (3 May 2024)
Q.1 Four children are sitting in a row. A is occupying the seat next to B but not next to C. If C is not sitting next to D, who is/are occupying seat/seats adjacent to D ? (CSE 2014)
(a) B
(b) A
(c) B and A
(d) Impossible to tell
Solution: (b)
Exp: The description is used to draw the following arrangement.
Thus option b is correct.
Q.2 Assume that-
- The hour and minute hands of a clock move without jerking.
- The clock shows a time between 8 o'clock and 9 o'clock.
- The two hands of the clock are one above the other.
After how many minutes (nearest integer) will the two hands be again lying one above the other? (CSE 2014)
(a) 60
(b) 62
(c) 65
(d) 67
Solution: (c)
When the minute hand travels 60 minutes, the hour hand only travels 5 minutes.
The relative time between both hands = 60 - 5 = 55 minutes.
They would meet again after = 60/55 = 1.09 hours
1.09 hours = 1.09 × 60 = 65.4 minutes.
They would meet again after 65 minutes.
Day 10 - (3 May 2024)
Q.1 Twelve people form a club. By picking lots one of them will host a dinner for all once in a month. The number of dinners a particular member has to host in one year is- (CSE 2014)
(a) One
(b) Zero
(c) Three
(d) Cannot be predicted
Solution: (d)
- We cannot predict the number of dinners for a particular member from the given data.
- It is a possibility that by choosing members from picking lots, one may have to host a dinner more than once.
Q.2 What is the missing number in the series 7 X 21 31 43 ? (CSE 2014)
(a) 11
(b) 12
(c) 13
(d) 14
Solution: (c)
The difference increases by 2 units in each step.
7 + 6 = 13
13 + 8 = 21
21 + 10 = 31
31 + 12 = 43
Thus 13 is the missing number.
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